Oh my goddddddddddddddddddddddddddddddddddddddd!!! This isn't as easy as I expected! Especially with the textbook answers all different from Darren's. Sh*t.....what's going onnn...?? The more I look at those unanswered questions, the more I go mumbo jumbo up in my head. I REALLY do get the concept. But what is up with those weird questions answers? =(
Nevermind. Let's get the concet straight first!
Given the polynomial function
y = x2 + 1
= (x + 1)(x – 1)
Solely from an equation, this is the information you need to spot in order to sketch the function's graph without using a graphing calculator.
i) The sum of exponents of all factors (the equation has 2 factors with an exponent of 1. Thus, The sum of exponents of the equation is 2. note: each bracket is a factor.)
ii) The sign in front of the product of all x's (x x x = x2 . Therefore, we can see that the sign in front of the product of all x's in the function is a positive sign)
iii) The x-intercept and y-intercept of the function (substitute y = 0 to get x-intercept and x = 0 to get y-intercept)
iv) The positive/negative sign of f(x) (substitute an x value to determine if f(x) is positive or negative at that particular x point)
Similarly, from a given graph, you will be able to identify and state the
i) Degree = 2 ; because it has n x-intercept, n - 1 local maximum/minimum point and its graph extends from quadrant 2 to quadrant 1. This information is enough to show that the graph has an even degree of 2 =D
ii) Sign of leading coefficient = Positive ; because the graph extends from quadrant 2 to quadrant 1
iii) x-intercept = -1, 1
y-intercept = -1
iv)
Intervals | x < -1 | -1 < x < 1 | x > 1 |
Sign of f(x) | + | - | + |
The new phrase of the day!
...has a zero at x = ? with order of ?...
Ok Ok...calm down. Read more, you'll understand better.
Let's say... y = -2 (x – 3)2
Expand it, x - 3 = 0
x = 3
Hence, the function has a zero at x = 3 with the order of 2
Not too difficult right? The term "with the order of" is basically just the highest power of the function
Ps: I found this site where this person posted a quartic function question and there were many comments posted there. I think the comments, explanations and answers really help. Click Here
Alright then...not-too-happy-math! Till I solve more questions!
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